50x^2-20x=4x^2

Solution for 50x^2-20x=4x^2 equation:

50x^2-20x=4x^2

We move all terms to the left:

50x^2-20x-(4x^2)=0

determiningTheFunctionDomain
50x^2-4x^2-20x=0

We add all the numbers together, and all the variables

46x^2-20x=0

a = 46; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·46·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*46}=\frac{0}{92}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*46}=\frac{40}{92}
=10/23
$